The following data for a random sample of banks in two cities represent the atm fees for using another bank's atm. compute the range and sample standard deviation for atm fees for each city. which city has the most dispersion based on range? which city has more dispersion based on the standard deviation? city a 1.251.25 1.001.00 1.501.50 1.501.50 1.501.50 city b 2.002.00 1.001.00 1.001.00 0.000.00 1.751.75 the range for city a is $0.500.50. the range for city b is $2.002.00.

Lol english

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60