Match each function formula with the corresponding transformation of the parent function y = - (x + 2)2. 1. y = - (x + 4)2 reflected across the x-axis and the y-axis 2. y = - (x + 2)2 - 2 translated right by 2 units 3. y = (x - 2)2 translated left by 2 units 4. y = 2 - (x + 2)2 translated down by 2 units 5. y = -x2 translated up by 2 units 6. y = (x + 2)2 reflected across the x-axis

So we are given the following function: .

Before we can solve this problem, we need to know the following:

Know we can solve the problem!

1.. Translated left by 2 units.

2.Translated down by 2 units

3.Reflected across the x-axis and the y-axis

4.Translated up by 2 units

5.Translated right by 2 units

6. y = (x + 2)2 Reflected across the x-axis

the least common denominator is 40

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.