If f(x)= 3/x+2-sqrt x-3, complete the following statement: the domain for f(x) is all real than or equal to 3.

all real numbers greater than or equal to 3

Step-by-step explanation:

There's some ambiguity in your "3/x+2-sqrt x-3."  I will assume that you meant:

   3

- sqrt(x - 3).       Using parentheses often changes everything.

 x + 2  

Here we see that x cannot = -2, because x + 2 would be zero then.  And x must be greater than or equal to 3, so that the input to the sqrt function will be 0 or greater.  The domain for f(x) is all real numbers greater than or equal to 3.  The prohibition against x = -2 has no bearing on the overall domain of this function.

what is the answer?