Solve the equation 2x^2+8x-1=0 by completing the square. give you answers correct to 2 decimal places.

The equations is needed to be solved by completing the squares.

The values of are

The equation is

Dividing the equation by

Finding

Adding it to the equation on both sides

The values of are

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x = ±2.12 - 2. Solving the quadratic equation 2x²+8x-1=0 by using completing the square, we obtain the roots x = 0.12 and x = -4.12.

We can solve the quadratic equation 2x²+8x-1=0 by completing the square follow the next steps:

Divide the coefficients of the equation by a (the coefficient x²)

(2x²+8x-1)/2=0 > x²+4x-1/2=0

Move the  independent term c/a to the right side of the equation

x²+4x = 1/2

Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation using (b/2)².

(b/2)²=(4/2)²=2²=4

x²+4x+4 = 1/2+4 > (x+2)² = 9/2

Applying square root on both sides of the equation

x+2 = √9/2

Finally, clear the x

x = √9/2 - 2 > x = ±2.12132 - 2

Correct to 2 decimal places

x = ± 2.12 - 2

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

it is x equals 3   plese mark me really need it

step-by-step explanation: