Iespoo1. a cylindrical swimming pool has a diameter 32 of feet and a height of 7 feet. about how many gallons ofwater can the pool contain? round your answer to the nearest whole number. (1 ft - 7.5 gal

42,223 gallons

Step-by-step explanation:

Find the volume of the pool and then multiply that by the conversion factor 1 ft³: 7.5 gallons.

If the pool diameter is 32 feet, then the pool radius is 16 feet.

The volume here is V = πr²h, or V = π(16 ft)²(7 ft) = 5629.73 ft³

Multiplying this volume by 1 ft³: 7.5 gallons, we get:

(5630 ft³)(7.5 gallons / 1 ft³) = 42,223 gallons

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."