Triangle xyz is translated 4 units up and 3 units left to yield ? x'y'z'. what is the distance between any two corresponding points on ? xyz and ? x'y'z?

5 units

Step-by-step explanation:

Let's take point X and X' (it will be the same regardless of the point).

The distance is 3 units to the right then 4 units up.

A direct line will be diagonal and can be found using the pythagorean theorem (refer to visual).

(D: a > 0) 3² + 4² = a² --> 9 + 16 = a² --> a² = 25 --> a = 5

So the distance is 5 units.

:

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet