Mathematics, 27.06.2019 15:40 stodd9503
The circle below is centered at (-1, 1) and has a radius of 3. what is its equation?
Answers: 2
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-1}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[2em] [x-(-1)]^2+[y-1]^2=3^2\implies (x+1)^2+(y-1)^2=9](/tpl/images/0023/8345/b8a5c.png)
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The circle below is centered at (-1, 1) and has a radius of 3. what is its equation?...
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