An olympian swam the 200-meter freestyle at a speed of 1.8 meters per second. an olympic runner ran the 200-meter dash in 21.3 seconds. how much faster was the runner’s speed than the swimmer’s speed to the nearest tenth of a meter per second?

7.6m/s

Step-by-step explanation:

Find the time the Olympian swam

Speed=distance/time ⇒⇒Time=distance/speed

Distance=200m , speed= 1.8m/s   t= 200/1.8 = 111.11 seconds

Find the speed of the Olympic runner

Distance=200m  time = 21.3 sec  

s=200/21.3 = 9.4 m/s

Difference in speed= 9.4-1.8= 7.6m/s

7.6 m/s faster

Step-by-step explanation:

Speed of swimmer = 1.8 meters per second

The distance covered by runner = 200

Time of runner = 21.3 sec

We have to find the speed of the runner first so that we can compare with the speed of swimmer.

Speed = Distance/Time

=> 200/21.3

=> 9.4 m/s

So we have to find the difference between both speeds

Difference = 9.4 - 1.8

=> 7.6 m/s

So the runner was 7.6 m/s faster..

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.