Find the perimeter of the rectangle

P = 2a²b(7a + 3). The perimeter of a rectangle that it has a width of 7a³b and a length of 3a²b is 2a²b(7a + 3).

The key to solve this problem is using the perimeter of the rectangle equation. The perimeter is equal to the sum of all sides.

P = w + l + w + l = 2 (w + l), where w is width and l is length.

With w = 7a³b and l = 3a²b:

P = 2(7a³b + 3a²b) = 2(7a³b) + 2(3a²b) = 14a³b+6a²b

We can factor 14a³b+6a²b as follow:

2a²b(7a + 3)

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