Hallar la ecuación de la circunferencia q pasa por el origen y tiene su centro en el punto común de las rectas: r: x+3y-6=0 y z: x-2y-1=0

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

idk

step-by-step explanation:

i would you but i don't under stand the qustion

step-by-step explanation: