What is the midpoint of a segment whose in endpoints are 5,8 and 11,6

8,7

Step-by-step explanation:

Add both "x" coordinates, divide by 2.

Add both "y" coordinates, divide by 2.

so x1+x2/2 and y1+y2/2

so 5,8 and 11,6 5+11=16 and then 16/2=8

then take your cords from y axis so 8+6=14 and then 14/2=7

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

6e14 is the answer.