20x-8y=-5 10x-4y=-4 can someone solve this

No Solution

When you do the substitution method, you would have the x and y variables equal to zero. In systems of equations, the equations are equal with each other.

20x-8y=-5
10x-4y=-4

20x-8y=-5
-2(10x-4y=-4)

20x-8y=-5
-20x+8y=8

The 20x and -20x cancel out
The -8y and 8y also cancel out. Thus leaving -5 and 8

According to system of equations, the equations must be equal. Additionally, -5 does not equal to 8.

Therefore, the answer is no solution.

Idon’t know the answer to this

The last answer choice