Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line. wlw. ооо win wiw

The slope of a line that is perpendicular to the given line is

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

Where "m" is the slope of the line and "b" is the y-intercept.

Solve for "y" from the equation of the line :

You can observe that the slope of this line is:

By definition, the slopes of perpendicular lines are negative reciprocal, then, the slope of a line that is perpendicular to the give line, is

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form