Asurveyor starts at the southeast corner of a lot andcharts the following displacements: a = 600 m, n; b = 400 m, w; c = 200 m, s; and d = 100 m, e. what is the net displacement from the starting point?

Find the difference vertically( North and South) and the difference horizontally ( East and West)

Then use  the Pythagorean Theorem.

600 North - 200 South = 400 m

400 West - 100 East = 300 m

Now using the Pythagorean Theorem;

400^2 + 300^2 = total displacement^2

Total displacement^2 = 160,000 + 90,000

Total displacement^2 = 250,000

Total displacement = √250,000

Total displacement = 500 m

a) 7x=7

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answer:

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