The height (in feet) of a rocket launched from the ground is given by the function f(t) = -16t2 + 160t. match each value of time elapsed (in seconds) after the rocket’s launch to the rocket's corresponding instantaneous velocity (in feet/second). t = 2 96 t = 3 -64 t = 4 32 t = 5 0 t = 6 -128 t = 7 -32 t = 8 t = 9

t = 2 s= 96

t = 3 s = 64

t = 4 s= 32

t= 5 s = 0

t= 6 s = -32

t = 7 s = -64

t = 8 s = -96

t= 9 s = -128

Step-by-step explanation:

We have the equation of the position of the rocket as a function of time t.

The instantaneous velocity of the rocket as a function of time is given by the derivation of the position with respect to time.

So

So

t = 2 s= 96

t = 3 s = 64

t = 4 s= 32

t= 5 s = 0

t= 6 s = -32

t = 7 s = -64

t = 8 s = -96

t= 9 s = -128

what is the question?

step-by-step explanation:

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.