Which is the axis of symmetry of a parabola with equation x^2=-4y?

x = 0

Step-by-step explanation:

Given

x² = - 4y ( divide both sides by - 4 )

y = - x²

Which is a parabola opening vertically down with it's vertex at (0, 0) and symmetrical about the y- axis

Hence equation of axis of symmetry is x = 0

nada

step-by-step explanation:

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.