Find the zeros of the following polynomial. 3x3 + 9x2 - 12x

If you factor 3x from the expression, you have

So, we have

We easily have

So, one solution is x=0.

The other solutions depend on the quadratic equation:

So, the solutions are

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i