The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21 what is the value of k in this equation?

The value of k =3

Step-by-step explanation:

We need to solve this equation to become in standard form to find the value of k.

The given standard form is:

Comparing it with

The value of k =3

k = 3

Step-by-step explanation:

Equation of the given function has been given as x² + y² - 6y - 12 = 0.

We have to convert this equation in the standard form of x² + (y - k)² = 21 to get the value of k.

x² + y² - 6y - 12 = 0

x² + y² - 6y + 9 - 9 - 12 = 0

x² + [y²- 2(3y) + 3²] - 21 = 0

x² + (y - 3)²- 21 = 0

x² + (y - 3)² = 21

Now by comparing this equation with the standard form of the equation we get the value of k = 3

i dont know sorry

step-by-step explanation:

mean, 40.6

step-by-step explanation: