45 points! asap and ill mark as brainliest! what are the amplitude, period, and midline of the function? (1 point) amplitude: 8; period: π; midline: y = 1 amplitude: 8; period: 2π; midline: y = 5 amplitude: 4; period: 2π; midline: y = 5 amplitude: 2; period: π; midline: y = 1

Amplitude = 2; period T = π; midline y = 1.

This sinusoidal wave is a even function which means that it has a positive half-cycle and a negative half-circle of equal size, from the image we can see that the midline is y = 1 which is the point where the function is centered.

The amplitude is the measure from the midline to the positive half-cycle, and the midline to the negative half-cycle which is 2.

The period corresponds to a complete cycle of the function or the repetition of the wave seen from a point. In this case, we can see that the wave, starting from π/2 it repeat in 3π/2. So, to calculate the period just substract 3π/2 by π/2

T = 3π/2 - π/2 = (3π - π)/2

T = 2π/2

T = π

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step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !