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![\bf 2y=-6x+8\implies y=\cfrac{-6x+8}{2}\implies y=\cfrac{-6x}{2}+\cfrac{8}{2} \\\\\\ y=-3x+4\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](/tpl/images/0016/6590/4dd88.png)
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Find the slope of a line perpendicular to 2y = -6x +8...
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