Coach johnson needs to buy shin guards for the junior varsity and varsity basketballplayers. the following packages of shin guards are available at the athletic store: . 10 shin guards for $14.50. 15 shin guards for $22.50coach johnson needs to buy 30 shin guards. how much money will he save by purchasing30 shin guards in packages with the lowest unit price compared to the highest unit price?

Coach Johnson will save $1.50

Step-by-step explanation:

1. The first step is to calculate the unit price for each of the packages, ie. how much a single shin guard costs.

If we look at the package of 10 shin guards for $14.50, we can calculate the unit price by dividing the package price ($14.50) by the number of shin guards (10). Thus we get:

14.50/10 = $1.45

Now, if we do the same for the package of 15 shin guards for $22.50, we get:

22.50/15 = $1.50

2. Now we can see that the lowest unit price is $1.45 (package of 10 shin guards) and the highest unit price is $1.50 (package of 15 shin guards).

3. There are two ways to see how much he would save, so I will show both here.

1) First calculate how much the coach will have to pay for a pack of 30 shin guards for each of the packages:

3 packages of 10 shin guards for $14.50 = 3*14.5 = $43.50

2 packages of 15 shin guards for $22.50 = 2*22.5 = $45.00

Now subtract the second value from the first: 45-43.5 = 1.5

Therefor, he will save $1.50.

2) The second method is perhaps what I would personally use as it is a little quicker; so we already know that the unit price for the pack of 10 is $1.45 and the unit price for the pack of 15 is $1.50 - thus, we can say that there is a difference of $0.05 per shin guard in price. Now if we were going to calculate how much the coach would save in buying 30 shin guards, we could simply multiply how much he saves on a single shin guard by 30. Thus, we get:

0.05*30 = 1.5

Therefor, again we get the same answer that Coach Johnson would save $1.50.

Hope that helps :)

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.