One sample has ss = 60 and a second sample has ss = 48.if n = 7 for both samples, find each of the sample variances and compute the pooled variance. because the samples are the same size, you should find that the pooled variance is exactly halfway between the two sample variances. the first sample has s2 = and the second has s2 = the pooled variance is s2p = assume that n = 7 for the first sample and n = 5 for the second. again, calculate the two sample variances and the pooled variance. you should find that the pooled variance is closer to the variance for the larger sample. the first sample has s2 = and the second has s2 = the pooled variance is s2p =

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

1. supplementary angles

2. acd and bcd

step-by-step explanation: