Use the taylor series you just found for sinc(x) to find the taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based at 0. a. give your answer using summation notation. b. give the interval on which the series converges.

In this question (link) I derived the Taylor series for about :

Then the Taylor series for

is obtained by integrating the series above:

We have , so and so

which converges by the ratio test if the following limit is less than 1:

Like in the linked problem, the limit is 0 so the series for converges everywhere.

step-by-step explanation:

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i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: