Two cyclists start at the same point and travel in opposite directions. one cyclist travels 10 km/ h slower than the other. if the two cyclists are 120 km apart after 2 hours, what is the rate of each cyclist?

A⇒35 km/hr

B⇒25 km/hr

Step-by-step explanation:

Let us call them cyclist A and B.

The rate of cyclist A will be x km/h

The rate of cyclist B will be (x-10) km/h

The total distance traveled= 120 km

Time taken =2 hours

Relative speed, since they are travelling in different directions, is arrived at by addition of their individual speeds = {x+ (x-10)}km/hr (2x-10)km/hr

Distance =speed × time

120km = (2x-10)km/hr×2

120=4x-20

4x=140

x= 35 km/hr⇒ speed for cyclist A

B⇒ (x-10) km/hr=35-10=25 km/hr

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: