1. y = sin? (in x). find dy show your work. en nuov vlomia a. sin (in x2) х cos? (in x) c. sin (in x) cos(inx) d. 2 sin (in x) cos(in x) e. none of the above.

dy/dx=  cos(ln(x))/x

Step-by-step explanation:

y=sin(ln(x)) given

We have to use chain rule to differentiate!

Let u=ln(x) then du/dx=1/x

So we have

if y=sin(ln(x)) then y=sin(u) and dy/dx=dy/du * du/dx=cos(u) *1/x

where again u=ln(x) so

dy/dx=cos(ln(x)) *1/x

dy/dx=cos(ln(x))/x

I hope I have the right intepretation because I do see a ? in between sin and (ln(x)) .

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome