The soccer team collected $800 at a car wash fundraiser. they charged $5 00 for small vehicles and $10 00 for larger vehicles. the amount collected can be modeled by the equation 5x+10y 800, where x represents the number of small vehicles and y represents the number of larger vehicles. if the number of larger vehicles washed was 50, how many small vehicles were washed in total?

You are told Y is the number of large vehicles washed and that there were 50 large vehicles.

Replace Y with 50 in the given equation to solve for x ( the number of small cars.

5x + 10(50) = 800

5x + 500 = 800

Subtract 500 from both sides:

5x = 300

Divide both sides by 5:

x = 300/5

x = 60

There were 60 small cars washed.

lol

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb