Mathematics, 24.06.2019 09:10 mcdonaldmacy01

Which of the following is the quotient of the rational expressions shown here?

Answers: 2

Show answers

Answers

Answer from: ricky9070

For this case we must find the quotient of the following expression:

$\frac {\frac {x} {x-1}} {\frac {1} {x + 1}}$

Applying double C we have the following expression:

$\frac {x (x + 1)} {x-1} =$

Applying distributive property to the terms within the parentheses of the numerator we have:

$\frac {x ^ 2 + x} {x-1}$

Thus, the quotient is given by option A

Option A

Answer from: smarty5187

The answer is option A. (x^2 + x)/(x-1)

Step-by-step explanation:

To solve this problem, we must first understand how to divide fractions. When dividing fractions, the first fraction is unchanged and is multiplied by the reciprocal of the second fraction. If we apply this knowledge to this problem, we get:

x/x-1 * x+1/1

When we multiply fractions, we simply multiply both of the numerators together and both of the denominators together to create a single fraction.

In this case we get:

x(x+1)/x-1

When we simplify this single fraction by using the distributive property, we get the following:

(x^2 + x)/(x-1)

Therefore, your answer is option A.

Hope this helps!

Answer from: Quest

(a) common ratio in the given sequence is, 3

(b) $6.973568802 \times 10^9$ push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

$a_n = a_1r^{n-1}$ , where r is the common ratio between the successive terms and $a_1$ is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term $(a_1) = 6$

then;

$a_n = a_ 1 \cdot r^{n-1}$

$a_{20} = 6 \cdot 3^{20-1}$

simplify:

$a_{20} = 6.973568802 \times 10^9$

therefore, $6.973568802 \times 10^9$ push ups will do kendall do on the 20th week

Answer from: Quest

45.36 feet per second

step-by-step explanation:

tyrone travels 30 miles in 58.2 minutes.

1 mile = 5280 feet; this means he travels

30(5280) = 158400 feet in 58.2 minutes.

1 minute = 60 seconds; this means he travels 158400 feet in

58.2(60) = 3492 seconds.

this gives us the unit rate of

158400/3492 = 45.36 feet per second.

Another question on Mathematics

Mathematics, 21.06.2019 19:00

What is the expression in factored form? -x^2 + 3x + 28 a. (x-7)(x-4) b. -(x-7)(x+4) c. (x+4)(x+7) d. -(x-4)(x+7)

Answers: 2

Answer

Mathematics, 21.06.2019 19:30

Fa bus driver leaves her first stop by 7: 00 a.m., her route will take less than 37 minutes. if she leaves after 7: 00 a.m., she estimates that the same route will take no less than 42 minutes. which inequality represents the time it takes to drive the route, r?

Answers: 3

Answer

Mathematics, 21.06.2019 23:20

The graph of y=x3 is transformed as shown in the graph below. which equation represents the transformed function?

Answers: 1

Answer

Mathematics, 22.06.2019 00:00

Aspacecraft can attain a stable orbit 300 kilometers above earth if it reaches a velocity of 7.7 kilometers per second. the formula for a rocket's maximum velocity v in kilometers per second is vequalsminus0.0098tplusc ln upper r, where t is the firing time in seconds, c is the velocity of the exhaust in kilometers per second, and r is the ratio of the mass of the rocket filled with fuel to the mass of the rocket without fuel. find the velocity of a spacecraft whose booster rocket has a mass ratio of 20, an exhaust velocity of 2.1 km/s, and a firing time of 15 s. can the spacecraft achieve a stable orbit 300 km above earth?