The length and width of a rectangle are consecutive odd integers. the area of the rectangle is 15 square units. what are the length and width of the rectangle? separate the answers with a comma.

3,5

Step-by-step explanation:

Represent the width by W and the length by L.  L = W + 2 (because L and W are consecutive odd integers).

Then L * W = 15 units^2, and after substitution this becomes:

(W + 2) * W = 15, or W^2 + 2W - 15 = 0.

This factors as follows:  (W + 5)(W - 3) = 0, and the positive root is W = 3.

The length and width of the rectangle are 3 and 5 respectively.

Note that 3 and 5 are consecutive odd integers, and that 3 * 5 = 15 units^2.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5