Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success is 40% round to the nearest tenth of a percent. i’ve searched around everywhere and 50 percent isn’t it 7.7% litereally i’m so stuck and i can’t go on with my work until i get two of these problems urgennntt

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to