Which point-slope equation represents a line that passes through (3,-2) with a slope of -4/5? y-3 = - 4/5(x + 2) y-2 = 4/5(x - 3) y +2=- 4/5(x - 3) y+3 = 4/5(x + 2)

answer:

idk

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

this is a good question! i'll do some research and come back when i have the answer!

b.   e = 7.5h

hope this , lovely!