Which equation can be solved to find one of the missing side lengths in the triangle? сos(60)=12/a cos(60)=12/b cos(60)=a/b cos(60)=a/12

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

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