What are the foci of the hyperbola whose equation is (x-6)^2/16-(y+7)^2/9 = 1? (1,−7) and (11,−7) (2,−7) and (10,−7) (6,−12) and (6,−2) (6,−10) and (6,−4)

i need a picure

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

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