How many real and complex roots exist for the polynomial f(x)=x^3+2x^x+4x+8? a. 1 real rootand 2 complex roots b. 2 real roots and 1 complex root c. 3 real roots and 0 complex roots d. 0 real roots and 3 complex roots

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

c

-by-step explanation:

it would be c

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.