Johan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. which explains whether his solutions are correct? he is correct because both solutions satisfy the equation. he is not correct because he made a sign error. he is not correct because there are no solutions. he is not correct because there is only one solution: x = 5.

He is not correct because he made a sign error.

Step-by-step explanation:

-2 |8-x| - 6 = -12

-2 |8-x| = -12 + 6

-2 |8-x| = - 6

2 |8-x| = 6

|8-x| = 3

2 possible solutions:

8-x = 3 > x = 5

or

8-x = -3  > x = 11

Comparing the answer choices, we can see that Johan got the sign of x = 11 wrong.

Hence the correct answer is:

He is not correct because he made a sign error.

8496 cars

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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