If the given solutions y⃗ 1(t)=[2e3t+4e−t3e3t+10e−t], y⃗ 2(t)=[−4e3t+2e−t−6e3t+5e−t]. form a fundamental set (i. e., linearly independent set) of solutions for the initial value problem y⃗ ′=[915−4−7]y⃗ , y⃗ (0)=[−30−55], impose the given initial condition and find the unique solution to the initial value problem. if the given solutions do not form a fundamental set, enter none in all of the answer blanks.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

the answer is d

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