Water at 1 atm and 15oc(kinematic viscosityν=1.13×10-6m2/s) is to be transported in a 150-mm-diameter, 300-m-long steel pipe. the absolute roughness of the pipe is 3mm. if the head loss in the pipe is 6 m, determine the volume flow rate of water. 14(10 pts) water at 15°c is drained from a large reservoir using two horizontal plastic pipes connected in series. the first pipe is 20 m long and has a 10-cm diameter, while the second pipe is 35 m long and has a 4-cm diameter. the water level in the reservoir is 18 m above the centerline of the pipe. the pipe entrance is sharp-edged, and the contraction between the two pipes is sudden. neglecting the effect of the kinetic energy correction factor, determine the discharge rate of water from the reservoir.

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140