Suppose that upper x has a discrete uniform distribution f left-parenthesis x right-parenthesis equals startlayout left-brace1st row 1st column 1 divided by 3, 2nd column x equals 1,2,3 2nd row 1st column 0, 2nd column otherwise endlayout a random sample of n equals 39 is selected from this population. find the probability that the sample mean is greater than 2.1 but less than 2.6. express the final answer to four decimal places (e. g. 0.9876). the probability is

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group