Urgent i can not figure this out ive gotten it wrong 3 times pleae

  see below for a graph

Step-by-step explanation:

Each of the functions:

will only be graphed in the specified domain. You know that ...

  y = -x

is a line with slope -1 through the origin. It won't go through the origin on your graph, because it stops at x = -2. f(x) is not defined as -(-2) at x=-2, so there will be an open circle at the end of this portion of the graph.

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You know that

  y = x+2

is a line with slope +1 through the y-intercept (0, 2). It will only be part of your graph for x-values between -2 and 2, inclusive. Because f(x) is defined as x+2 at the end points of this segment, those points will be shown as solid dots.

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You know that

  y = 5

is a horizontal line. It will be part of your graph for x > 2, and will have an open circle on the end at x=2. f(2) is not defined as 5, but is defined as 4 (see above), which is why the circle is open.

if im undersanding the question correctly, its organized from 10

step-by-step explanation: