What is the midpoint of (3.2,2.5) and (1,6,-4.5)

(2.4 , -1)

Step-by-step explanation:

Too many commas in second ordered pair but this is how I will interpret the question:

Find the midpoint of (3.2,2.5) and (1.6,-4.5)

So just average x's  : (3.2+1.6)/2 =4.8/2=2.4

And

    just average y's : (2.5+-4.5)/2=-2/2=-1

The midpoint is (average x's , average y's)

Your midpoint is (2.4             ,     -1             )

answer (2.4 , -1)

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles