Quadrilateral opqr is inscribed inside a circle as shown below. what is the measure of angle q? you must show all work and calculations to receive credit. circle n is shown with an inscribed quadrilateral labeled opqr. o is labeled 2x degrees. p is labeled y degrees. q is labeled 2x plus 4 degrees. r is labeled 3y plus 8 degrees.

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

q: 92 degrees

hope i ^-^

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

a is the right answer