Me maths. in a triangle abc, ad is the bisector of angle a ab=5.6cm ,ac=4cm and dc=3cm, find bd and dcpls me

Step-by-step

Given:

In a triangle ABC, AD is the bisector of angle A ....If AB=5.6cm ,AC=4cm and DC=3cm, find BD and DC

This problem can be solved by direct application of the angle bisector theorem, which states that the division of the side opposite to the bisected angles is proportional to the respective sides.

Here we have:

Bisector: AD

Side divided: DC = 3 cm

Length of AB = 5.6

Length of AC = 4.0

Then BD = AB/AC * DC = 5.6/4.0 * 3 = 4.2

BC = BD+DC = 4.2+3 = 7.2

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.