Find the root(s) of f (x) = (x- 6)2(x + 2)2.

Assumption: is defined for all (all real values of .)

Step-by-step explanation:

Evaluating for a root of this function shall give zero.

Equate and zero to find the root(s) of .

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Multiply both sides by 1/4:

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This polynomial has two factors:

Apply the factor theorem:

X=6 , X = -2

Step-by-step explanation:

For any polynomial given in factorised form , the roots are determined as explained below:

Suppose we have a polynomial

(x-m)(x-n)(x+p)(x-q)

The roots of above polynomial will be m,n,-p, and q

Also if we have same factors more than once , there will be duplicate roots.

Example

(x-m)^2(x-n)(x+p)^2

For above polynomial

There will be total 5 roots . Out of which 2(m and -p) of them will be repeated. x=m , x=n , x =-p

Hence in our problem

The roots of f(x)= (x-6)^2(x+2)^2 are

x=6 And x=-2

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

£56

step-by-step explanation: