You invested $5000 between two accounts paying 4% and 9% annual interest, respectively. if the total interest earned for theyear was $350, how much was invested at each rate? $was invested at 4% andwas invested at 9%.

Part 1) The amount invested at 4% was $2,000

Part 2) The amount invested at 9% was $3,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x------> the amount invested at 4%

5,000-x ----> the amount invested at 9%

in this problem we have

substitute in the formula above

so

therefore

The amount invested at 4% was $2,000

The amount invested at 9% was $3,000