Let f(x) = 5/x and g(x)=2x2+5x. what two numbers are not in the domain of f o g

0 and -5/2

Step-by-step explanation:

g is the first function we consider because that is the function we are first plugging in values into since the order is f o g and not g o f.

g has domain all real numbers meaning you can plug in any number into g and get a number back

So now let's look at plugging in g(x) into f(x)

that is f(g(x))=f(2x^2+5x)=5/(2x^2+5x)

Here you are dividing by a variable

You have to watch out dividing by 0

The variable, 2x^2+5x, is 0 when

2x^2+5x=0

x(2x+5)=0

x=0 or x=-5/2

So The domain is all real numbers except x=0 or x=-5/2

well what did you do it matters what you did : )

step-by-step explanation: