Answer this two poles, ab and ed, are fixed to the ground with the of ropes ac and ec, as shown: two right triangles abc and edc have a common vertex c. angle abc and edc are right angles. ab is labeled 13 feet, ac is labeled 15 feet, ec is labeled 10 feet, and ed is labeled 4 feet. what is the approximate distance, in feet, between the two poles? 11.14 feet16.65 feet14.35 feet15.59 feet

Applying the Pythagorean Theorem, the approximate distance in feet, between the two poles is: b. 16.65 feet

Recall:

For a right triangle where c is the hypotenuse and a and b are the other legs of the right triangle, the Pythagorean Theorem states that: c² = a² + b².

The distance between the two poles = BC + DC

Given:

Apply the Pythagorean Theorem to find BC and DC respectively.

Length of BC:

BC = √(AC² - AB²)

BC = √(15² - 13²)

BC = 7.48 feet

Length of DC:

DC = √(EC² - ED²)

DC = √(10² - 4²)

DC = 9.17 feet

The distance between the two poles = 7.48 + 9.17 = 16.65 feet

Learn more about Pythagorean Theorem on:

link

Check the picture below.

so we can simply use the pythagorean theorem for each triangle and get "w" and "z".

sine

step-by-step explanation: