Triangle abc is translated 2 units right and 5 units down to form triangle a′b′c′. this triangle is then translated 5 units right and 4 units up to form triangle a″b″c″. if vertex a is at (-4, 2), what are the coordinates of vertex a″? a. (3, -1) b. (3, 1) c. (-4, -2) d. (2, -4) e. (-11, 1)

B

Step-by-step explanation:

So, for this problem, it is only asking for vertex A, so you only have to apply the transformations to one point (unless you want to find out where the other points are at).

Vertex A is at (-4,2).

The triangle is first translated 2 units right and 5 units down.

So to find the coordinate of that you have to understand that is you translate something right or left, the x value will change. And if it's up or down, the y value will change. If you are going right or up, the amount it's moved will be added. And left or down will be subtracted.

-4+2=-2 (so the new x-value will be -2)

2-5=-3 (so the new y-value will be -3)

Thus vertex A' is (-2,-3).

Now for the next transformation.

(-2,-3) is moved 5 units right and 4 units up.

-2+5=3 (so x-value will be 3)

-3+4=1 (so the y-value will be 1)

SO, the new coordinate of vertex A" is...

(3,1)! aka B

(Also, you can just illustrate this on a graph but i'm showing it to you this way because when you get more advanced the amount it is being translated will be much higher.)

the answer will be b x² +x-1

step-by-step explanation:

a

step-by-step explanation:

strong negative correlation