Eric wants to sell his car that he paid $7,000 for 3 years ago. the car depreciated, or decreased in value, at a constant rate each month over a 3-year period. if x represents the monthly depreciation amount, which expression shows how much eric can sell his car for today?

a.7,000 − 3x
b.7,000 + 3x
c.7,000 − 36x
d.7,000 + 36x

Option C. 7,000 − 36x

Step-by-step explanation:

Let

y > depreciated value of the car

x---> rate of depreciation

t > the time in months

we know that

The linear equation that represent this situation is

y=7,000-xt

For

t=3 years

Convert to months

t=3*12=36 months

substitute

y=7,000-x(36)

y=7,000-36x

c

step-by-step explanation:

idk what the heck he answer is, i’m just putting this here so i finish my account