What are the solutions of the quadratic equation
4x2 - 30x + 45 = 0

Step-by-step explanation:

note :

the discriminat of each quadratic equation : ax²+bx+c=0 (a ≠ 0) is :

Δ = b² -4ac

1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a

2 ) Δ = 0 : one solution : x = -b/2a

3 ) Δ < 0 : no reals solutions

in this exercice : 4x²-30x+45=0

a= 4    b= -30  c=45

Δ = (-30)² - 4(4)(45) = 900 - 720 = 180continu

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17