Mathematics, 29.01.2020 23:57 michaelwthms
Explain the process for factoring each of the following: a. x^2-25 b. 3x^2-12x-15 c. x^3+2x^2+3x+6
Answers: 1
Mathematics, 22.06.2019 01:30
Novak gives 9 packs of paper to a group of 5 students. if the group shares the paper equally how many packs of paper does each student get. write the a answer as a mixed number
Answers: 1
Mathematics, 22.06.2019 01:30
Acell phone company offers two plans to its subscribers. at the time new subscribers sign up, they are asked to provide some demographic information. the mean yearly income for a sample of 40 subscribers to plan a is $45,000 with a standard deviation of $9,200. for a sample of 25 subscribers to plan b, the mean income is $64,300 with a standard deviation of $7,100. at the 0.025 significance level, is it reasonable to conclude the mean income of those selecting plan b is larger? assume unequal population standard deviations. hint: for the calculations, assume the plan a as the first sample. what is the decision rule? (negative amount should be indicated by a minus sign. round your answer to 3 decimal places.) compute the value of the test statistic. (negative amount should be indicated by a minus sign. round your answer to 2 decimal places.) what is your decision regarding h0 ? reject h0 fail to reject h0 compute the p-value. less than 0.01 between 0.01 and 0.025 between 0.025 and 0.05 between 0.05 and 0.10 greater than 0.10
Answers: 3
Mathematics, 22.06.2019 04:30
What is the hypotenuse of a triangle with 4 ft and 5 ft
Answers: 1
Mathematics, 22.06.2019 04:50
Astudy claims that the mean age of online dating service users is 40 years. some researchers think this is not accurate and want to show that the mean age is not 40 years. identify the null hypothesis, h0, and the alternative hypothesis, ha, in terms of the parameter μ. select the correct answer below: h0: μ≥40; ha: μ< 40 h0: μ≤40; ha: μ> 40 h0: μ≠40; ha: μ=40 h0: μ=40; ha: μ≠40
Answers: 3
Explain the process for factoring each of the following: a. x^2-25 b. 3x^2-12x-15 c. x^3+2x^2+3x+6...
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