The sum of eli’s age and cecil’s age is 60. six years ago, eli was three times old as cecil. find eli’s age now

Eli's age = 42 years

Step-by-step explanation:

Let x be Eli's age and y be Cecil's age

So,

According to the statement given

x+y=60     eqn 1

Eli's age 6 years ago = x-6

Cecil's age 6 years ago = y-6

So according to the given statement

x-6 = 3(y-6)

x-6 = 3y - 18

x-3y = -18+6

x-3y= -12      eqn 2

Subtracting eqn 2 from eqn 1

x+y - (x-3y) = 60 - (-12)

x+y-x+3y = 60+12

4y = 72

y = 18

Cecil's age = 18 years

Putting y = 18 in eqn 1

x+18=60

x = 60-18

x = 42

Eli's age = 42 years ..

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

there's the chart